How do you factor the quadratic equation #12(a-2)^4 + 52(a-2)^2 - 40#? Algebra Polynomials and Factoring Factoring Completely 1 Answer James May 11, 2018 the answer #12a^4-96a^3+313a^2-592a+360# Explanation: show below #12(a-2)^4 + 52(a-2)^2 - 40# #12(a-2)^2*(a-2)^2+52(a-2)^2-40# #12*(a^2-4a+4)*(a^2-4a+4)+52(a^2-4a+4)-40# #12a^4-96a^3+288a^2-384a+192+52a^2-208a+208-40# #12a^4-96a^3+313a^2-592a+360# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1750 views around the world You can reuse this answer Creative Commons License