How do you factor the quadratic equation $12(a-2)^4 + 52(a-2)^2 - 40$ ?

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Answer 1 · 2018-05-11T01:17:19

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$12a^4-96a^3+313a^2-592a+360$

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$12(a-2)^4 + 52(a-2)^2 - 40$

$12(a-2)^2*(a-2)^2+52(a-2)^2-40$

$12*(a^2-4a+4)*(a^2-4a+4)+52(a^2-4a+4)-40$

$12a^4-96a^3+288a^2-384a+192+52a^2-208a+208-40$

$12a^4-96a^3+313a^2-592a+360$

How do you factor the quadratic equation 12(a-2)^4 + 52(a-2)^2 - 4012(a-2)^4 + 52(a-2)^2 - 40?