How do you factor the monomial #95xy^2# completely? Algebra Polynomials and Factoring Monomial Factors of Polynomials 1 Answer smendyka Sep 3, 2017 See a solution process below: Explanation: #95xy^2 = 5 xx 19 xx x xx y xx y# #5# and #19# are both prime numbers so they cannot be factored any further. Answer link Related questions What are Monomial Factors of Polynomials? How do you factor polynomials by finding the greatest common factor? How can a factoring problem be checked? How do you find the greatest common factors of variable expressions? How do you factor #3a+9b+6#? What is the greatest common factor of #a^3-3a^2+4a#? How do you factor #12xy+24xy^2+36xy^3#? How do you find the greatest common factor of #45y^{12}+30y^{10}#? How do you factor #92x^10y^4 - 54x^12y^9#? How do you factor #4x^2+x#? See all questions in Monomial Factors of Polynomials Impact of this question 1784 views around the world You can reuse this answer Creative Commons License