How do you factor the expression #x^3-3x^2-4x+12#?
1 Answer
May 10, 2016
Explanation:
Factor by grouping:
#x^3-3x^2-4x+12#
#=(x^3-3x^2)-(4x-12)#
#=x^2(x-3)-4(x-3)#
#=(x^2-4)(x-3)#
#=(x-2)(x+2)(x-3)#
