How do you factor the expression $r^{2} - 4 r s + 4 s^{2}$ $r^2-4rs+4s^2$ ?

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How do you factor the expression $r^{2} - 4 r s + 4 s^{2}$ $r^2-4rs+4s^2$ ?

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Answer 1 · 2018-06-11T05:34:38

$r^{2} - 4 r s + 4 s^{2} = {(r - 2 s)}^{2}$ $r^2 - 4rs +4s^2 = (r - 2s)^2$

Explanation:

$r^{2} - 4 r s + 4 s^{2}$ $r^2 -4rs + 4s^2$
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$= r^{2} - 2 (r) (2 s) + {(2 s)}^{2}$ $=r^2 -2 (r)(2s) + (2s)^2$
$" "$
$= {(r - 2 s)}^{2}$ $=(r - 2s)^2$

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How do you factor the expression $r^{2} - 4 r s + 4 s^{2}$ $r^2-4rs+4s^2$ ?

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