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How do you factor the expression #9x^2-25#?

1 Answer

Jan 6, 2016

#(3x)^2-(5)^2=(3x+5)(3x-5)#

Explanation:

#9x^2-25# fits the form #a^2-b^2#, where #a=3x# and #b=5#. Rewrite the expression as #(3x)^2-(5)^2#.

Use the difference of squares: #a^2-b^2=(a+b)(a-b)#.

#(3x)^2-(5)^2=(3x+5)(3x-5)#

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