How do you factor the expression #6x^2 + 5x +1#?

1 Answer
smendyka
Apr 21, 2018

See a solution process below:

Explanation:

Because the constant is #1# we know the constant for the factored terms will also be #1#:

#( 1)( 1)#

Because the constant is a positive and the coefficient for the #x# term is also positive we know the signs for the constants in the factors will both be positive:

#( + 1)( + 1)#

Now we need to determine the factors which multiply to 6 and also add to 5 for the coefficients of the #x# terms in the factors:

#1 xx 6 = 6#; #1 + 6 = 7# <- this is not the factor

#2 xx 3 = 6#; #2 + 3 = 5 # <- this IS the factor

#(2x + 1)(3x + 1)#

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