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How do you factor the expression #49y^2 + 112y + 64#?

1 Answer

Lucio Falabella

Jan 11, 2016

#49y^2+112y+64=(7y+8)^2#

Explanation:

#49y^2+112y+64=7^2y^2+2*7*8y+8^2=#
#=(7y)^2+2*7*8y+8^2#

Use the Square of a binomial rule

#(a+b)^2=(a^2+2ab+b^2)#

with:

#a=7y#
#b=8#

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