How do you factor the expression #3x^2-3x-18#?

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How do you factor the expression #3x^2-3x-18#?

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Answer 1 · 2016-01-15T06:55:58

Take three common and then find the roots of the quadratic equation.

Explanation:

#3x^2-3x-18=3(x^2-x-9)#
for the quadratic equation #x^2-x-9=0# a=1, b=-1, c=-9
#x=(-b+-sqrt(b^2-4ac))/(2a)#
#x=(1+-sqrt(37))/2#
therefore
#3x^2-3x-18=3(x-(1+sqrt(37))/2)(x-(1-sqrt(37))/2)#

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How do you factor the expression #3x^2-3x-18#?

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