How do you factor the expression $3 x^{2} - 3 x - 18$ $3x^2-3x-18$ ?

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How do you factor the expression $3 x^{2} - 3 x - 18$ $3x^2-3x-18$ ?

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Answer 1 · 2016-01-15T06:55:58

Take three common and then find the roots of the quadratic equation.

Explanation:

$3 x^{2} - 3 x - 18 = 3 (x^{2} - x - 9)$ $3x^2-3x-18=3(x^2-x-9)$
for the quadratic equation $x^{2} - x - 9 = 0$ $x^2-x-9=0$ a=1, b=-1, c=-9
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$
$x = \frac{1 \pm \sqrt{37}}{2}$ $x=(1+-sqrt(37))/2$
therefore
$3 x^{2} - 3 x - 18 = 3 (x - \frac{1 + \sqrt{37}}{2}) (x - \frac{1 - \sqrt{37}}{2})$ $3x^2-3x-18=3(x-(1+sqrt(37))/2)(x-(1-sqrt(37))/2)$

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How do you factor the expression $3 x^{2} - 3 x - 18$ $3x^2-3x-18$ ?

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How do you factor the expression $3 x^{2} - 3 x - 18$ $3x^2-3x-18$ ?