How do you factor the expression #-14x+8+6x^2#?

1 Answer
Nghi N.
Jul 19, 2016

2(x - 1)(3x - 4)

Explanation:

Bring the expression to standard form:
#f(x) = 6x^2 - 14x + 8#
Since a + b + c = 0
- One real root is (1) and the factor is (x - 1)
- One real root is #(c/a = 8/6)# and the factor is #(x - 8/6)#
Factor form of f(x):
#f(x) = a(x - x1)(x - x2) = 6(x - 1)(x - 8/6) = (x - 1)(6x - 8) = 2(x - 1)(3x - 4)#

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