How do you factor the expression $12w^2 -27$ ?

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Answer 1 · 2015-12-13T16:56:50

$3(2w+3)(2w-3)$

Factor out a common multiple of both terms. In this case, it's $3$ .

$3(4w^2-9)$

Now, notice that $4w^2-9$ is a difference of squares.

A typical difference of squares in the form $a^2-b^2$ can be factorized into $(a+b)(a-b)$ .

Thus, $4w^2-9=(2w+3)(2w-3)$ .

So, the complete factored form is:

$3(2w+3)(2w-3)$

How do you factor the expression 12w^2 -2712w^2 -27?