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How do you factor #(t+u)^3-64#?

1 Answer

May 7, 2015

Use a³ - b³ = (a - b)(a² + ab + b²)

#a-](t+u)^3#
#b-]64#

#therefore (t+u)^3-64#
#=(t+u−64){(t+u)^2+(t+u)(64)+64^2}#

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