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How do you factor #t^2 + t +48#?

1 Answer

Shwetank Mauria

May 8, 2018

#t^2+t+48=(t+1/2+sqrt91/2i)(t+1/2-sqrt91/2i)#

Explanation:

#t^2+t+48#

= #t^2+2xxtxx1/2+(1/2)^2-(1/2)^2+48#

= #(t+1/2)^2+191/4#

= #(t+1/2)^2-(sqrt191/2i)^2#, where #i^2=-1#

= #(t+1/2+sqrt91/2i)(t+1/2-sqrt91/2i)#

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