How do you factor $s^2-9$ ?

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Answer 1 · 2015-05-08T22:55:05

To factor $s^2-9$ , you will need to use the difference of two squrares. This property tells us that $(x^2-y^2)$ can be rewritten as $(x-y)(x+y)$

In this case, $s^2-9$ will become $(s-3)(s+3)$ , which is the answer you are looking for.

How do you factor s^2-9 s^2-9?