How do you factor $p(x)= 2x^3-x^2-18x+9$ ?

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Answer 1 · 2015-09-19T03:07:10

$(x-3)(x+3)(2x-1)$

$p(x)=2x^3−x^2−18x+9$

$=x^2(2x - 1) -9(2x-1)$

$=(x^2-9)(2x-1)$

$=(x-3)(x+3)(2x-1)$

How do you factor p(x)= 2x^3-x^2-18x+9p(x)= 2x^3-x^2-18x+9?