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How do you factor #p^2+11p+10#?

1 Answer

May 17, 2015

Notice that #11 = 10 + 1# and #10 = 10 xx 1#.

#p^2+11p+10#

#= p^2 + (10+1)p + (10xx1) = (p+10)(p+1)#

In general note that #(p+a)(p+b) = p^2+(a+b)p+(axxb)p#

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