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How do you factor #n^4 - 1#?

1 Answer

Dec 17, 2015

#(n-1)(n+1)(n^2+1)#

Explanation:

By using this formula #a^2-b^2 = (a-b)(a+b)#

here we have #a = n^2# and #b = 1#

#(n^2)^2 - 1# (remember #(a^n)^m = a^(nm)#)

#(n^2-1)(n^2+1)#

You do it again with #(n^2-1)(n^2+1)# and you have your answer

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