How do you factor #n^2-2n-35#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Binayaka C. Feb 3, 2017 #(n-7)(n+5)# Explanation: #n^2-2n-35 = n^2-7n +5n-35 = n(n-7) + 5(n-7) = (n-7)(n+5)#[Ans] Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 3378 views around the world You can reuse this answer Creative Commons License