How do you factor $k^{2} + k - 110$ $k^2 + k - 110$ ?

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Answer 1 · 2018-03-11T14:04:00

$(k - 10) (k + 11)$ $color(blue)((k-10)(k+11)$

Given:

Factorize: $k^{2} + k - 110$ $color(red)(k^2 + k - 110$

$y = f (x) = k^{2} + k - 110$ $y=f(x) = k^2 + k - 110$

Split the middle term to factorize.

$k^{2} - 10 k + 11 k - 110$ $k^2 -10k+11k - 110$

Break the expression into appropriate groups.

Factor $k$ $k$ and $11$ $11$ respectively as shown below:

$k (k - 10) + 11 (k - 10)$ $k(k-10)+11(k-10)$

Next, factor the common term: $(k - 10)$ $(k-10)$

$(k - 10) (k + 11)$ $color(blue)((k-10)(k+11)$

Hope you find this solution useful.

How do you factor k^2 + k - 110k2+k−110k^2 + k - 110?