How do you factor fully, if possible 21c^4d^3-28c^2d^5+7cd^3?

1 Answer
smendyka
Nov 14, 2016

7cd^3(3c^3 - 4cd^2 + 1)

Explanation:

You find the lowest form of each constant and variable which is present in each term and factor it out. In this case it would be 7, c^1 = c and d^3 giving:

7cd^3(3c^(4-1)d^(3-3) - 4c^(2 - 1)d^(5-3) + 1c^(1-1)d^(3-3))

7cd^3(3c^3d^0 - 4cd^2 + 1c^0d^0)

7cd^3(3c^3 - 4cd^2 + 1)

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