How do you factor $d²-8d+15$ ?

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Answer 1 · 2015-11-24T22:25:25

$d^2-8d+15=(d-3)(d-5)$

$d^2-8d+15$

Find two numbers that when added equal $-8$ and when multiplied equal $15$ . The numbers $-3$ and $-5$ meet the criteria.

$(d-3)(d-5)$

How do you factor d²-8d+15d²-8d+15?