How do you factor completely $x²+3x+4x+12$ ?

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Answer 1 · 2015-11-17T12:40:53

$x^2+3x+4x+12=(x+3)(x+4)$

$x^2+3x+4x+12$

Factor out common terms from both pairs of terms.

$x(x+3)+4(x+3)$

Factor out the common term $(x+3)$ .

$(x+3)(x+4)$

How do you factor completely x²+3x+4x+12x²+3x+4x+12?