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How do you factor completely # x^3 - 9x #?

1 Answer

Shwetank Mauria

Aug 1, 2016

#x^3-9x=x(x+3)(x-3)#

Explanation:

#x^3-9x#

= #x(x^2-9)#

= #x(x^2-3^2)#

Now using identity #a^2-b^2=(a+b)(a-b)#, we get

#x(x^2-3^2)#

= #x(x+3)(x-3)#

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