How do you factor completely x^3 - 4x^2 + 4x - 16?
1 Answer
Dec 31, 2015
Factor by grouping to find:
x^3-4x^2+4x-16=(x^2+4)(x-4)
Explanation:
x^3-4x^2+4x-16
=(x^3-4x^2)+(4x-16)
=x^2(x-4)+4(x-4)
=(x^2+4)(x-4)
If we allow Complex coefficients...
=(x-2i)(x+2i)(x-4)