How do you factor completely $x^{2} - 7 x + 6$ $x^2 - 7x + 6$ ?

Question

1436 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-09T22:51:53

$(x - 1) (x - 6)$ $(x-1)(x-6)$

Let's do a little thought experiment:

What two numbers sum up to the middle term ( $- 7$ $-7$ ) and have a product of the last term ( $6$ $6$ )?

After some trial and error, we arrive at $- 1$ $-1$ and $- 6$ $-6$ , which means we can factor this as

$(x - 1) (x - 6)$ $(x-1)(x-6)$

Hope this helps!

How do you factor completely x^2 - 7x + 6x2−7x+6x^2 - 7x + 6?