How do you factor completely #x^2 – 3x – 18#?
1 Answer
Aug 22, 2016
Explanation:
Find a pair of factors of
#x^2-3x-18=x^2-(6-3)x-(6*3)=(x-6)(x+3)#
Find a pair of factors of
#x^2-3x-18=x^2-(6-3)x-(6*3)=(x-6)(x+3)#