How do you factor completely $x^{2} + 12 x y + 35 y^{2}$ $x^2 + 12xy + 35y^2$ ?

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How do you factor completely $x^{2} + 12 x y + 35 y^{2}$ $x^2 + 12xy + 35y^2$ ?

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Answer 1 · 2016-04-25T11:10:51

$x^{2} + 12 x y + 35 y^{2}$ $x^2 + 12xy+35y^2$
$= x^{2} + 2 . x .6 y + 35 y^{2}$ $=x^2+2.x.6y+35y^2$
$= x^{2} + 2 . x .6 y + {(6 y)}^{2} - y^{2}$ $=x^2+2.x.6y+(6y)^2-y^2$
$= {(x + 6 y)}^{2} - y^{2}$ $= (x+6y)^2-y^2$
$= (x + 6 y + y) \cdot (x + 6 y - y)$ $= (x+6y+y)*(x+6y-y)$
$= (x + 7 y) (x + 5 y)$ $=(x+7y)(x+5y)$

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How do you factor completely $x^{2} + 12 x y + 35 y^{2}$ $x^2 + 12xy + 35y^2$ ?

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How do you factor completely $x^{2} + 12 x y + 35 y^{2}$ $x^2 + 12xy + 35y^2$ ?