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How do you factor completely #bx^2-b = x-b^2x#?

1 Answer

Shwetank Mauria

May 2, 2018

#x=1/b# or #x=-b#

Explanation:

#bx^2-b=x-b^2x#

#=>bx^2+b^2x-x-b=0#

or #bx(x+b)-1(x+b)=0#

or #(bx-1)(x+b)=0#

i.e. either #bx-1=0# i.e. #x=1/b#

or #x+b=0# i.e. #x=-b#

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