How do you factor completely #a^2 + 2ac - ab - bc + c^2#?
1 Answer
Aug 28, 2016
Explanation:
#a^2+2ac-ab-bc+c^2#
#=(a^2+2ac+c^2)-(ab+bc)#
#=(a+c)^2-b(a+c)#
#=((a+c)-b)(a+c)#
#=(a+c-b)(a+c)#
