How do you factor completely #9x^4 - 12x^2 +4 = 0#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Ratnaker Mehta Mar 2, 2018 #:. x=+-sqrt(2/3)#. Explanation: I hope the Problem is to solve the eqn. # 9x^4-12x^2+4=0#. #9x^4-12x^2+4=0#. #:. (3x^2)^2-2(3x^2)(2)+(2)^2=0#. #:. (3x^2-2)^2=0#. #:. 3x^2=2, or, x^2=2/3#. #:. x=+-sqrt(2/3)#. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3446 views around the world You can reuse this answer Creative Commons License