How do you factor completely #12z^2+7z-12#?

2 Answers
F. Javier B.
May 19, 2018

See below

Explanation:

Two alternatives: use quadratic formula or complete square (a little bit complicate in this case). The use of Riffini's method is also available but in this case is not quite evident

Quadratic formula:

#12z^2+7z-12=0#

#z=(-7+-sqrt(49+576))/24=(-7+-25)/24# from here two solutions

#z=3/4# and #z=-4/3#

Then factoring is #(z-3/4)(z+4/3)=12z^2+7z-12#

Cem Sentin
May 19, 2018

#(3z+4)*(4z-3)#

Explanation:

#12z^2+7z-12#

=#12z^2+16z-9z-12#

=#4z*(3z+4)-3*(3z+4)#

=#(3z+4)*(4z-3)#

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