How do you factor completely #64-x^3#?
1 Answer
Sep 2, 2016
Explanation:
The difference of cubes identity can be written:
#a^3-b^3 = (a-b)(a^2+ab+b^2)#
Note both
So we find:
#64-x^3 = 4^3-x^3#
#color(white)(64-x^3) = (4-x)(4^2+4x+x^2)#
#color(white)(64-x^3) = (4-x)(16+4x+x^2)#
