How do you factor completely #4x^3 - 36x#?
1 Answer
Mar 14, 2018
Explanation:
#"take out a "color(blue)"common factor of 4x"#
#=4x(x^2-9)#
#x^2-9" is a "color(blue)"difference of squares"#
#•color(white)(x)a^2-b^2=(a-b)(a+b)#
#rArrx^2-9=(x-3)(x+3)#
#rArr4x^3-36x=4x(x-3)(x+3)#
