How do you factor completely #49x^2 - 25y^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nam D. Mar 28, 2018 #(7x-5y)(7x+5y)# Explanation: Given: #49x^2-25y^2# Apply the identity: #a^2-b^2=(a-b)(a+b)# Here, #a^2=49x^2,b^2=25y^2# #:.a=sqrt(49x^2)=7x,b=sqrt(25y^2)=5y# And so, #49x^2-25y^2=(7x-5y)(7x+5y)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5642 views around the world You can reuse this answer Creative Commons License