How do you factor completely $3x^2+6x-24$ ?

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How do you factor completely $3x^2+6x-24$ ?

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Answer 1 · 2017-03-10T19:19:40

$3x^2+6x-24 = 3(x+4)(x-2)$

Explanation:

Note that all of the terms are divisible by $3$ , so we can separate that out as a factor first, then note that $8$ is the product of $4$ and $2$ , which differ by $2$ , so we find:

$3x^2+6x-24 = 3(x^2+2x-8) = 3(x+4)(x-2)$

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How do you factor completely $3x^2+6x-24$ ?

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How do you factor completely $3x^2+6x-24$ ?