How do you factor completely #3a^2+12a-15#?

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How do you factor completely #3a^2+12a-15#?

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Answer 1 · 2016-06-10T13:34:21

(x - 1)(3x + 15)

Explanation:

#y = 3a^2 + 12a - 15#
Since a + b + c = 0, use shortcut.
One real root is x = 1 and the factor is (x - 1)
One real roots is #c/a = -15/3#, and the factor is #(x + 15/3)#
#y = (x -1)(x + 15/3) = (x - 1)(3x + 15)#

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How do you factor completely #3a^2+12a-15#?

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