How do you factor completely $3 a^{2} + 12 a - 15$ $3a^2+12a-15$ ?

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How do you factor completely $3 a^{2} + 12 a - 15$ $3a^2+12a-15$ ?

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Answer 1 · 2016-06-10T13:34:21

(x - 1)(3x + 15)

Explanation:

$y = 3 a^{2} + 12 a - 15$ $y = 3a^2 + 12a - 15$
Since a + b + c = 0, use shortcut.
One real root is x = 1 and the factor is (x - 1)
One real roots is $\frac{c}{a} = - \frac{15}{3}$ $c/a = -15/3$ , and the factor is $(x + \frac{15}{3})$ $(x + 15/3)$
$y = (x - 1) (x + \frac{15}{3}) = (x - 1) (3 x + 15)$ $y = (x -1)(x + 15/3) = (x - 1)(3x + 15)$

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How do you factor completely $3 a^{2} + 12 a - 15$ $3a^2+12a-15$ ?

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