How do you factor completely #2x^3y^4 − 8x^2y^3 + 6xy^2#?
1 Answer
Aug 18, 2016
Explanation:
Separate out the common factor
#2x^3y^4-8x^2y^3+6xy^2#
#=2xy^2(x^2y^2-4xy+3)#
#=2xy^2((xy)^2-4(xy)+3)#
#=2xy^2(xy-3)(xy-1)#
