How do you factor completely #2x^2 - 32#?
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"How does Bohr improve Rutherford's atomic model?"
1 Answer
Apr 26, 2016
Explanation:
Separate out the common scalar factor
#a^2-b^2 = (a-b)(a+b)#
with
#2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x-4)(x+4)#
