How do you factor completely $2 x^{2} - 12 x + 18$ $2x^2 − 12x + 18$ ?

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Answer 1 · 2016-05-31T12:46:48

It is

$2 x^{2} - 12 x + 18 = 2 \cdot (x^{2} - 6 x + 9) = 2 \cdot {(x - 3)}^{2}$ $2x^2 − 12x + 18 =2*(x^2-6x+9)=2*(x-3)^2$

How do you factor completely 2x^2 − 12x + 18 2x2−12x+182x^2 − 12x + 18 ?