How do you factor completely #25x^2 -y^4#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Shwetank Mauria Jul 21, 2016 #25x^2-y^4=(5x+y^2)(5x-y^2)# Explanation: As #25x^2-y^4# is difference of two squares, to factorize it we can use the identity #a^2-b^2=(a+b)(a-b)# Hence #25x^2-y^4=(5x)^2-(y^2)^2# = #(5x+y^2)(5x-y^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2118 views around the world You can reuse this answer Creative Commons License