How do you factor completely #18a^2be^2-48abc^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer sankarankalyanam Jun 15, 2018 #color(crimson)(=> 6 ab(3ae^2 - 8 c^3)# Explanation: #18a^^2be^2 - 48abc^3# #=> 6 * 3 * a * a * b * e^2 - 6 * 8 * a 8 b * c^3# #color(crimson)(=> 6 ab(3ae^2 - 8 c^3), " Taking common terms out"# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1378 views around the world You can reuse this answer Creative Commons License