How do you factor completely $14 g h - 18 h$ $14gh-18h$ ?

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Answer 1 · 2018-04-06T08:53:16

$14 g h - 18 h = 2 h (7 g - 9)$ $14gh-18h=2h(7g-9)$

to factorise we will take out the hcf rof each like term

$14 g h - 18 h$ $14gh-18h$

$h c f (14, 18) = 2$ $hcf(14,18)=2$

$14 g h - 18 h = 2 (7 g h - 9 h)$ $14gh-18h=color(red)(2)(7gh-9h)$

there is only $1$ $1$ $g$ $g$ term

$h c f (h, h) = h$ $hcf(h,h)=h$

$14 g h - 18 h = 2 h (7 g - 9)$ $14gh-18h=2color(red)(h)(7g-9)$

$14 g h - 18 h = 2 h (7 g - 9)$ $14gh-18h=2h(7g-9)$

How do you factor completely 14gh−18h14gh-18h?