How do you factor #c^2 + 7c +12#?

1 Answer
Shwetank Mauria
Jul 19, 2016

#c^2+7c+12=(c+4)(c+3)#

Explanation:

To factorize #ax^2+bx+c#, one should split #b# in two parts whose product is #ac#. In #c^2+7c+12#, one needs to split #7# in two parts whose product is #1×12=12#. Such numbers are #3# and #4#.

Hence, #c^2+7c+12#

= #c^2+3c+4c+12#

= #c(c+3)+4(c+3)#

= #(c+4)(c+3)#

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