How do you factor and solve $x^{2} + 5 x - 24 = 0$ $x^2+5x-24=0$ ?

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Answer 1 · 2015-05-31T12:49:32

Look for a pair of factors of $24$ $24$ whose difference is $5$ $5$ .

$24 = 8 \times 3$ $24 = 8 xx 3$ and $5 = 8 - 3$ $5 = 8 - 3$

So

$x^{2} + 5 x - 24$ $x^2+5x-24$

$= x^{2} + (8 - 3) x - (8 \times 3)$ $= x^2+(8-3)x-(8xx3)$

$= (x + 8) (x - 3)$ $= (x+8)(x-3)$

So the solutions of $x^{2} + 5 x - 24 = 0$ $x^2+5x-24 = 0$ are $x = - 8$ $x=-8$ and $x = 3$ $x=3$

How do you factor and solve x^2+5x-24=0x2+5x−24=0x^2+5x-24=0?