How do you factor a^3b^3-16ab^3a3b3−16ab3?
1 Answer
May 6, 2016
Explanation:
Looking for common factors in the 2 terms.
from
a^3" and a we get " aa3 and a we get a from
b^3 and" b^3→ b^3b3andb3→b3
rArra^3b^3-16ab^3=ab^3(a^2-16)⇒a3b3−16ab3=ab3(a2−16) now
a^2-16" is a" color(blue)" difference of squares"a2−16 is a difference of squares and in general factorises as
a^2-b^2=(a-b)(a+b)a2−b2=(a−b)(a+b) For
a^2-16 , a=a " and " b=4→ (a-4)(a+4)a2−16,a=a and b=4→(a−4)(a+4)
rArrcolor(red)(|bar(ul(color(white)(a/a)color(black)(a^3b^3-16ab^3=ab^3(a-4)(a+4))color(white)(a/a)|))