How do you factor #a^2-x^2+10x-25#? Algebra Polynomials and Factoring Factoring Completely 1 Answer ali ergin Aug 9, 2016 #(a-x+5)(a+x-5)# Explanation: #a^2-x^2+10x-25=a^2-(x^2-10x+25)# #x^2-10x+25=(x-5)^2# #a^2-(x-5)^2# #m^2-n^2=(m-n)(m+n)# #(a-(x-5))(a+(x-5))# #(a-x+5)(a+x-5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 865 views around the world You can reuse this answer Creative Commons License