How do you factor #(a^2 + 4)^2 - 25a^2 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. May 31, 2015 #y = (a^2 + 4 - 5a)(a^2 + 4 + 5a) =# = #(a^2 - 5a + 4)(a^2 + 5a + 4)# = [(a - 1)(a - 4)][(a + 1)(a + 4)] Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1308 views around the world You can reuse this answer Creative Commons License