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How do you factor #a^2+11a+18#?

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May 16, 2015

#a^2+11a+18 = (a+9)(a+2)#

To find this factorization, I noticed that #11 = 2+9# and #18 = 2xx9#.

This is an instance of the general observation that:

#(a+m)(a+n) = a^2 + (m+n)a + (mxxn)#

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