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How do you factor #9x - 64x^3#?

1 Answer

Aug 31, 2017

We have #9x - 64x^3 = f(x)#

#implies f(x) = x(9-64x^2)#
#implies f(x) = x(3^2 - (8x)^2)#
#implies f(x) = x(3 + 8x)(3 - 8x)#

And that's it.

#9x - 64x^3 = x(3 + 8x)(3 - 8x)#

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