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How do you factor #9u^2+24uv+16v^2#?

1 Answer

Jul 22, 2016

#(3u+4v)^2#.

Explanation:

Let us remember the Identity # : a^2+2ab+b^2=(a+b)^2#.

Now, #9u^2+24uv+16v^2#

#=(3u)^2+2*3u*4v+(4v)^2#

#=(3u+4v)^2#.

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