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How do you factor #9c^2 - 25d^4#?

1 Answer

Mar 30, 2016

#9c^2-25d^4=(3c-5d^2)*(3c+5d^2)#

Explanation:

#9c^2-25d^4=(3c)^2-(5d^2)^2#

#3c=a#
#5d^2=b#

#(3c)^2-(5d^2)^2=a^2-b^2#

#a^2-b^2=(a-b)*(a+b)#

#9c^2-25d^4=(3c-5d^2)*(3c+5d^2)#

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